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In parallelogram ABCD, two points P and Q are taken on diagonal BD such that DP = BQ Show that: i) ΔAPD ≅ ΔCQB ii) AP = CQ iii) ΔAQB ≅ ΔCPD iv) AQ = CP

DP = c sin o cosec B , = a sino cosec A = AP ' BP ' CP ' = c sin o cosec A DP'd sino cosec B b sin o cosec B Hence may be obtained the following results

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